How much does a 2 inch steel ball weigh?
Views: 394 Update Date:Apr 16 , 2024
The weight of a steel ball depends on its density. Assuming the steel is of average density, which is around 7.85 grams per cubic centimeter, we can calculate the weight of a 2-inch diameter steel ball.
First, let's convert the diameter from inches to centimeters: 2 inches * 2.54 cm/inch = 5.08 cm
Next, let's calculate the volume of the ball using the formula for the volume of a sphere: Volume = (4/3) * π * r^3
where r is the radius of the sphere (half of the diameter), so in our case, r = 2.54 cm.
Volume = (4/3) * π * (2.54 cm)^3 ≈ 68.05 cubic centimeters
Now, to find the weight, we multiply the volume by the density:
Weight = Volume * Density
Weight ≈ 68.05 cm^3 * 7.85 g/cm^3 ≈ 534.43 grams
So, a 2-inch diameter steel ball would weigh approximately 534.43 grams.
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First, let's convert the diameter from inches to centimeters: 2 inches * 2.54 cm/inch = 5.08 cm
Next, let's calculate the volume of the ball using the formula for the volume of a sphere: Volume = (4/3) * π * r^3
where r is the radius of the sphere (half of the diameter), so in our case, r = 2.54 cm.
Volume = (4/3) * π * (2.54 cm)^3 ≈ 68.05 cubic centimeters
Now, to find the weight, we multiply the volume by the density:
Weight = Volume * Density
Weight ≈ 68.05 cm^3 * 7.85 g/cm^3 ≈ 534.43 grams
So, a 2-inch diameter steel ball would weigh approximately 534.43 grams.
